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4112304213301 is a prime number
BaseRepresentation
bin111011110101111000011…
…011101000110100110101
3112120010120112212211201121
4323311320123220310311
51014333444334311201
612425055543023541
7603050506033444
oct73657033506465
915503515784647
104112304213301
111346022580299
12564baa43abb1
1323aa337b445b
1410307256ad5b
1571e855079a1
hex3bd786e8d35

4112304213301 has 2 divisors, whose sum is σ = 4112304213302. Its totient is φ = 4112304213300.

The previous prime is 4112304213293. The next prime is 4112304213337. The reversal of 4112304213301 is 1033124032114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3221217300625 + 891086912676 = 1794775^2 + 943974^2 .

It is a cyclic number.

It is not a de Polignac number, because 4112304213301 - 23 = 4112304213293 is a prime.

It is a super-2 number, since 2×41123042133012 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4112304213371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056152106650 + 2056152106651.

It is an arithmetic number, because the mean of its divisors is an integer number (2056152106651).

Almost surely, 24112304213301 is an apocalyptic number.

It is an amenable number.

4112304213301 is a deficient number, since it is larger than the sum of its proper divisors (1).

4112304213301 is an equidigital number, since it uses as much as digits as its factorization.

4112304213301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 4112304213301 its reverse (1033124032114), we get a palindrome (5145428245415).

The spelling of 4112304213301 in words is "four trillion, one hundred twelve billion, three hundred four million, two hundred thirteen thousand, three hundred one".