Base | Representation |
---|---|
bin | 10010101100111100111001… |
… | …00010100101011101010111 |
3 | 12101121200211000220122221112 |
4 | 21112132130202211131113 |
5 | 20342310432132434343 |
6 | 223245242104205235 |
7 | 11443215603332432 |
oct | 1126363442453527 |
9 | 171550730818845 |
10 | 41126938171223 |
11 | 12116922469893 |
12 | 474281446981b |
13 | 19c433b2b6108 |
14 | a227a94cc819 |
15 | 4b4c155dd218 |
hex | 25679c8a5757 |
41126938171223 has 2 divisors, whose sum is σ = 41126938171224. Its totient is φ = 41126938171222.
The previous prime is 41126938171213. The next prime is 41126938171273. The reversal of 41126938171223 is 32217183962114.
It is a happy number.
It is an a-pointer prime, because the next prime (41126938171273) can be obtained adding 41126938171223 to its sum of digits (50).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41126938171223 - 226 = 41126871062359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41126938171213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20563469085611 + 20563469085612.
It is an arithmetic number, because the mean of its divisors is an integer number (20563469085612).
Almost surely, 241126938171223 is an apocalyptic number.
41126938171223 is a deficient number, since it is larger than the sum of its proper divisors (1).
41126938171223 is an equidigital number, since it uses as much as digits as its factorization.
41126938171223 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 870912, while the sum is 50.
The spelling of 41126938171223 in words is "forty-one trillion, one hundred twenty-six billion, nine hundred thirty-eight million, one hundred seventy-one thousand, two hundred twenty-three".
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