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411312101 is a prime number
BaseRepresentation
bin11000100001000…
…001111111100101
31001122221211010112
4120201001333211
51320243441401
6104451502405
713123044434
oct3041017745
91048854115
10411312101
111a11a1962
12b58b7a05
13672a2455
143c8ab11b
152619a3bb
hex18841fe5

411312101 has 2 divisors, whose sum is σ = 411312102. Its totient is φ = 411312100.

The previous prime is 411312089. The next prime is 411312103. The reversal of 411312101 is 101213114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 260661025 + 150651076 = 16145^2 + 12274^2 .

It is a cyclic number.

It is not a de Polignac number, because 411312101 - 210 = 411311077 is a prime.

Together with 411312103, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (411312103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205656050 + 205656051.

It is an arithmetic number, because the mean of its divisors is an integer number (205656051).

Almost surely, 2411312101 is an apocalyptic number.

It is an amenable number.

411312101 is a deficient number, since it is larger than the sum of its proper divisors (1).

411312101 is an equidigital number, since it uses as much as digits as its factorization.

411312101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

The square root of 411312101 is about 20280.8308754844. The cubic root of 411312101 is about 743.6875235423.

Adding to 411312101 its reverse (101213114), we get a palindrome (512525215).

The spelling of 411312101 in words is "four hundred eleven million, three hundred twelve thousand, one hundred one".