4113320003431 has 2 divisors, whose sum is σ = 4113320003432. Its totient is φ = 4113320003430.

The previous prime is 4113320003413. The next prime is 4113320003449. The reversal of 4113320003431 is 1343000233114.

4113320003431 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (4113320003413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (4113320003413) and next prime (4113320003449).

It is a cyclic number.

It is not a de Polignac number, because 4113320003431 - 2¹⁷ = 4113319872359 is a prime.

It is a super-2 number, since 2×4113320003431² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4113320003396 and 4113320003405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4113320003131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056660001715 + 2056660001716.

It is an arithmetic number, because the mean of its divisors is an integer number (2056660001716).

Almost surely, 2^{4113320003431} is an apocalyptic number.

4113320003431 is a deficient number, since it is larger than the sum of its proper divisors (1).

4113320003431 is an equidigital number, since it uses as much as digits as its factorization.

4113320003431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 4113320003431 its reverse (1343000233114), we get a palindrome (5456320236545).

The spelling of 4113320003431 in words is "four trillion, one hundred thirteen billion, three hundred twenty million, three thousand, four hundred thirty-one".