Base | Representation |
---|---|
bin | 10010101101001010010011… |
… | …10111101000010000111000 |
3 | 12101122101102000112001001201 |
4 | 21112211021313220100320 |
5 | 20342420210111112100 |
6 | 223252432532223544 |
7 | 11443562235332026 |
oct | 1126451167502070 |
9 | 171571360461051 |
10 | 41134141113400 |
11 | 12119989325965 |
12 | 47440a476abb4 |
13 | 19c4c1866658a |
14 | a22c8dd95716 |
15 | 4b4ed7b4336a |
hex | 256949de8438 |
41134141113400 has 24 divisors (see below), whose sum is σ = 95636878089120. Its totient is φ = 16453656445280.
The previous prime is 41134141113383. The next prime is 41134141113437. The reversal of 41134141113400 is 431114143114.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 102835352584 + ... + 102835352983.
It is an arithmetic number, because the mean of its divisors is an integer number (3984869920380).
Almost surely, 241134141113400 is an apocalyptic number.
41134141113400 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
41134141113400 is an abundant number, since it is smaller than the sum of its proper divisors (54502736975720).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
41134141113400 is a wasteful number, since it uses less digits than its factorization.
41134141113400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 205670705583 (or 205670705574 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 41134141113400 its reverse (431114143114), we get a palindrome (41565255256514).
The spelling of 41134141113400 in words is "forty-one trillion, one hundred thirty-four billion, one hundred forty-one million, one hundred thirteen thousand, four hundred".
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