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4113530203093 is a prime number
BaseRepresentation
bin111011110111000001100…
…000011010101111010101
3112120020201222210120112221
4323313001200122233111
51014344002212444333
612425421340142341
7603123053545633
oct73670140325725
915506658716487
104113530203093
1113465a16185a3
12565290b379b1
1323ab9a7a84bc
1410314b304353
1572007e78d2d
hex3bdc181abd5

4113530203093 has 2 divisors, whose sum is σ = 4113530203094. Its totient is φ = 4113530203092.

The previous prime is 4113530203091. The next prime is 4113530203157. The reversal of 4113530203093 is 3903020353114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2964395514564 + 1149134688529 = 1721742^2 + 1071977^2 .

It is a cyclic number.

It is not a de Polignac number, because 4113530203093 - 21 = 4113530203091 is a prime.

It is a super-2 number, since 2×41135302030932 (a number of 26 digits) contains 22 as substring.

Together with 4113530203091, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4113530203091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056765101546 + 2056765101547.

It is an arithmetic number, because the mean of its divisors is an integer number (2056765101547).

Almost surely, 24113530203093 is an apocalyptic number.

It is an amenable number.

4113530203093 is a deficient number, since it is larger than the sum of its proper divisors (1).

4113530203093 is an equidigital number, since it uses as much as digits as its factorization.

4113530203093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 29160, while the sum is 34.

The spelling of 4113530203093 in words is "four trillion, one hundred thirteen billion, five hundred thirty million, two hundred three thousand, ninety-three".