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4113544541 is a prime number
BaseRepresentation
bin1111010100101111…
…1011010101011101
3101121200100201021112
43311023323111131
531411031411131
61520103311405
7203636360141
oct36513732535
911550321245
104113544541
111820a96997
1296974b565
135072c8232
142b046d221
1519120302b
hexf52fb55d

4113544541 has 2 divisors, whose sum is σ = 4113544542. Its totient is φ = 4113544540.

The previous prime is 4113544511. The next prime is 4113544543. The reversal of 4113544541 is 1454453114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3347085316 + 766459225 = 57854^2 + 27685^2 .

It is a cyclic number.

It is not a de Polignac number, because 4113544541 - 214 = 4113528157 is a prime.

Together with 4113544543, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 4113544498 and 4113544507.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4113544543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056772270 + 2056772271.

It is an arithmetic number, because the mean of its divisors is an integer number (2056772271).

Almost surely, 24113544541 is an apocalyptic number.

It is an amenable number.

4113544541 is a deficient number, since it is larger than the sum of its proper divisors (1).

4113544541 is an equidigital number, since it uses as much as digits as its factorization.

4113544541 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 19200, while the sum is 32.

The square root of 4113544541 is about 64136.9202643844. The cubic root of 4113544541 is about 1602.2811915003.

Adding to 4113544541 its reverse (1454453114), we get a palindrome (5567997655).

The spelling of 4113544541 in words is "four billion, one hundred thirteen million, five hundred forty-four thousand, five hundred forty-one".