Base | Representation |
---|---|
bin | 111011110111011111111… |
… | …101110011000000010100 |
3 | 112120022001121100222112021 |
4 | 323313133331303000110 |
5 | 1014401024023034030 |
6 | 12425544153102524 |
7 | 603141530252314 |
oct | 73673775630024 |
9 | 15508047328467 |
10 | 4114041221140 |
11 | 134683401aa64 |
12 | 5653b40b7a44 |
13 | 23ac4c61a646 |
14 | 103199127444 |
15 | 72037c6b97a |
hex | 3bddff73014 |
4114041221140 has 24 divisors (see below), whose sum is σ = 8736559450920. Its totient is φ = 1627126414848.
The previous prime is 4114041221113. The next prime is 4114041221167. The reversal of 4114041221140 is 411221404114.
It is an interprime number because it is at equal distance from previous prime (4114041221113) and next prime (4114041221167).
It can be written as a sum of positive squares in 4 ways, for example, as 58175510416 + 4055865710724 = 241196^2 + 2013918^2 .
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1155627777 + ... + 1155631336.
It is an arithmetic number, because the mean of its divisors is an integer number (364023310455).
Almost surely, 24114041221140 is an apocalyptic number.
It is an amenable number.
4114041221140 is an abundant number, since it is smaller than the sum of its proper divisors (4622518229780).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4114041221140 is a wasteful number, since it uses less digits than its factorization.
4114041221140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2311259211 (or 2311259209 counting only the distinct ones).
The product of its (nonzero) digits is 1024, while the sum is 25.
Adding to 4114041221140 its reverse (411221404114), we get a palindrome (4525262625254).
The spelling of 4114041221140 in words is "four trillion, one hundred fourteen billion, forty-one million, two hundred twenty-one thousand, one hundred forty".
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