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412230341381 is a prime number
BaseRepresentation
bin1011111111110101101…
…01111101001100000101
31110102001001010002022112
411333322311331030011
523223221431411011
6513213114510405
741532311041655
oct5777265751405
91412031102275
10412230341381
1114990a30a951
1267a87135405
132cb47421631
1415d48620365
15aaca4b858b
hex5ffad7d305

412230341381 has 2 divisors, whose sum is σ = 412230341382. Its totient is φ = 412230341380.

The previous prime is 412230341363. The next prime is 412230341399. The reversal of 412230341381 is 183143032214.

It is a balanced prime because it is at equal distance from previous prime (412230341363) and next prime (412230341399).

It can be written as a sum of positive squares in only one way, i.e., 285914784100 + 126315557281 = 534710^2 + 355409^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-412230341381 is a prime.

It is a super-2 number, since 2×4122303413812 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (412230341581) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206115170690 + 206115170691.

It is an arithmetic number, because the mean of its divisors is an integer number (206115170691).

Almost surely, 2412230341381 is an apocalyptic number.

It is an amenable number.

412230341381 is a deficient number, since it is larger than the sum of its proper divisors (1).

412230341381 is an equidigital number, since it uses as much as digits as its factorization.

412230341381 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 32.

Adding to 412230341381 its reverse (183143032214), we get a palindrome (595373373595).

The spelling of 412230341381 in words is "four hundred twelve billion, two hundred thirty million, three hundred forty-one thousand, three hundred eighty-one".