Base | Representation |
---|---|
bin | 1011111111111110011… |
… | …11000100011100001101 |
3 | 1110102020011210000222002 |
4 | 11333333033010130031 |
5 | 23223344313033144 |
6 | 513224310202045 |
7 | 41534164313642 |
oct | 5777717043415 |
9 | 1412204700862 |
10 | 412304033549 |
11 | 149947972971 |
12 | 67aa7953325 |
13 | 2cb59783875 |
14 | 15d54323dc9 |
15 | aad1bc314e |
hex | 5fff3c470d |
412304033549 has 2 divisors, whose sum is σ = 412304033550. Its totient is φ = 412304033548.
The previous prime is 412304033539. The next prime is 412304033551. The reversal of 412304033549 is 945330403214.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 326898062500 + 85405971049 = 571750^2 + 292243^2 .
It is a cyclic number.
It is not a de Polignac number, because 412304033549 - 212 = 412304029453 is a prime.
Together with 412304033551, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (412304033539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206152016774 + 206152016775.
It is an arithmetic number, because the mean of its divisors is an integer number (206152016775).
Almost surely, 2412304033549 is an apocalyptic number.
It is an amenable number.
412304033549 is a deficient number, since it is larger than the sum of its proper divisors (1).
412304033549 is an equidigital number, since it uses as much as digits as its factorization.
412304033549 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 155520, while the sum is 38.
The spelling of 412304033549 in words is "four hundred twelve billion, three hundred four million, thirty-three thousand, five hundred forty-nine".
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