Base | Representation |
---|---|
bin | 101110111100111111000011… |
… | …1111001011100110011100111 |
3 | 2000011022121110021202120020221 |
4 | 1131321332013321130303213 |
5 | 413113111134242403143 |
6 | 4022214303520105211 |
7 | 152664261365060152 |
oct | 13571760771346347 |
9 | 2004277407676227 |
10 | 413002040200423 |
11 | 10a6601aa830143 |
12 | 3a3a268b765207 |
13 | 1495ac04ab734b |
14 | 73db5965d0c99 |
15 | 32b31e69692ed |
hex | 1779f87e5cce7 |
413002040200423 has 2 divisors, whose sum is σ = 413002040200424. Its totient is φ = 413002040200422.
The previous prime is 413002040200271. The next prime is 413002040200457. The reversal of 413002040200423 is 324002040200314.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 413002040200423 - 233 = 412993450265831 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (413002040200723) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206501020100211 + 206501020100212.
It is an arithmetic number, because the mean of its divisors is an integer number (206501020100212).
Almost surely, 2413002040200423 is an apocalyptic number.
413002040200423 is a deficient number, since it is larger than the sum of its proper divisors (1).
413002040200423 is an equidigital number, since it uses as much as digits as its factorization.
413002040200423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 25.
Adding to 413002040200423 its reverse (324002040200314), we get a palindrome (737004080400737).
The spelling of 413002040200423 in words is "four hundred thirteen trillion, two billion, forty million, two hundred thousand, four hundred twenty-three".
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