Base | Representation |
---|---|
bin | 1100000001010100001… |
… | …00001011111101011011 |
3 | 1110111002020220001021021 |
4 | 12000222010023331123 |
5 | 23231332241213201 |
6 | 513423455423311 |
7 | 41561041116634 |
oct | 6005204137533 |
9 | 1414066801237 |
10 | 413022601051 |
11 | 14a186544305 |
12 | 68068524b37 |
13 | 2cc425c4338 |
14 | 15dc193288b |
15 | ab24d11ea1 |
hex | 602a10bf5b |
413022601051 has 2 divisors, whose sum is σ = 413022601052. Its totient is φ = 413022601050.
The previous prime is 413022601049. The next prime is 413022601127. The reversal of 413022601051 is 150106220314.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 413022601051 - 21 = 413022601049 is a prime.
Together with 413022601049, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (413022601021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206511300525 + 206511300526.
It is an arithmetic number, because the mean of its divisors is an integer number (206511300526).
Almost surely, 2413022601051 is an apocalyptic number.
413022601051 is a deficient number, since it is larger than the sum of its proper divisors (1).
413022601051 is an equidigital number, since it uses as much as digits as its factorization.
413022601051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 413022601051 its reverse (150106220314), we get a palindrome (563128821365).
The spelling of 413022601051 in words is "four hundred thirteen billion, twenty-two million, six hundred one thousand, fifty-one".
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