Base | Representation |
---|---|
bin | 111100000110110000111… |
… | …111111010000001110110 |
3 | 112121212100222121102120202 |
4 | 330012300333322001312 |
5 | 1020133111334123410 |
6 | 12441254512200502 |
7 | 604261661121143 |
oct | 74066077720166 |
9 | 15555328542522 |
10 | 4130433114230 |
11 | 13527858a3945 |
12 | 568609839132 |
13 | 23c662637177 |
14 | 103cb214d3ca |
15 | 72696d73ca5 |
hex | 3c1b0ffa076 |
4130433114230 has 32 divisors (see below), whose sum is σ = 7465404312000. Its totient is φ = 1645381251072.
The previous prime is 4130433114229. The next prime is 4130433114259. The reversal of 4130433114230 is 324113340314.
It is a happy number.
It is a super-2 number, since 2×41304331142302 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4130433114193 and 4130433114202.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1606934 + ... + 3292886.
It is an arithmetic number, because the mean of its divisors is an integer number (233293884750).
Almost surely, 24130433114230 is an apocalyptic number.
4130433114230 is a deficient number, since it is larger than the sum of its proper divisors (3334971197770).
4130433114230 is a wasteful number, since it uses less digits than its factorization.
4130433114230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1686968.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 4130433114230 its reverse (324113340314), we get a palindrome (4454546454544).
The spelling of 4130433114230 in words is "four trillion, one hundred thirty billion, four hundred thirty-three million, one hundred fourteen thousand, two hundred thirty".
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