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4132233230231 is a prime number
BaseRepresentation
bin111100001000011100010…
…010110011011110010111
3112122001000102211210111202
4330020130102303132113
51020200303201331411
612442153255023115
7604354406630561
oct74103422633627
915561012753452
104132233230231
111353519a27717
12568a3066aa9b
1323c88b567c72
14104003256331
157274ee0183b
hex3c21c4b3797

4132233230231 has 2 divisors, whose sum is σ = 4132233230232. Its totient is φ = 4132233230230.

The previous prime is 4132233230219. The next prime is 4132233230233. The reversal of 4132233230231 is 1320323322314.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4132233230231 - 234 = 4115053361047 is a prime.

It is a super-2 number, since 2×41322332302312 (a number of 26 digits) contains 22 as substring.

Together with 4132233230233, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 4132233230194 and 4132233230203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4132233230233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2066116615115 + 2066116615116.

It is an arithmetic number, because the mean of its divisors is an integer number (2066116615116).

Almost surely, 24132233230231 is an apocalyptic number.

4132233230231 is a deficient number, since it is larger than the sum of its proper divisors (1).

4132233230231 is an equidigital number, since it uses as much as digits as its factorization.

4132233230231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 4132233230231 its reverse (1320323322314), we get a palindrome (5452556552545).

The spelling of 4132233230231 in words is "four trillion, one hundred thirty-two billion, two hundred thirty-three million, two hundred thirty thousand, two hundred thirty-one".