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41325012102301 is a prime number
BaseRepresentation
bin10010110010101101110101…
…01010101010110010011101
312102022122002010221220120221
421121112322222222302131
520404032111044233201
6223520240512041341
711463430216063234
oct1131267252526235
9172278063856527
1041325012102301
1112192925a99994
124775092b33251
131a09c16574b25
14a2c1d987bb1b
154b9e599054a1
hex2595baaaac9d

41325012102301 has 2 divisors, whose sum is σ = 41325012102302. Its totient is φ = 41325012102300.

The previous prime is 41325012102299. The next prime is 41325012102313. The reversal of 41325012102301 is 10320121052314.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 33308469279801 + 8016542822500 = 5771349^2 + 2831350^2 .

It is a cyclic number.

It is not a de Polignac number, because 41325012102301 - 21 = 41325012102299 is a prime.

Together with 41325012102299, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41325012702301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20662506051150 + 20662506051151.

It is an arithmetic number, because the mean of its divisors is an integer number (20662506051151).

Almost surely, 241325012102301 is an apocalyptic number.

It is an amenable number.

41325012102301 is a deficient number, since it is larger than the sum of its proper divisors (1).

41325012102301 is an equidigital number, since it uses as much as digits as its factorization.

41325012102301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 41325012102301 its reverse (10320121052314), we get a palindrome (51645133154615).

The spelling of 41325012102301 in words is "forty-one trillion, three hundred twenty-five billion, twelve million, one hundred two thousand, three hundred one".