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413311224341 is a prime number
BaseRepresentation
bin1100000001110110100…
…01001100101000010101
31110111211100222121222202
412000323101030220111
523232430133134331
6513512245534245
741601144304151
oct6007321145025
91414740877882
10413311224341
1114a314458254
1268129114385
132cc8a33aa52
141600bdc4061
15ab40324ecb
hex603b44ca15

413311224341 has 2 divisors, whose sum is σ = 413311224342. Its totient is φ = 413311224340.

The previous prime is 413311224317. The next prime is 413311224343. The reversal of 413311224341 is 143422113314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 379585371025 + 33725853316 = 616105^2 + 183646^2 .

It is a cyclic number.

It is not a de Polignac number, because 413311224341 - 238 = 138433317397 is a prime.

Together with 413311224343, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (413311224343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206655612170 + 206655612171.

It is an arithmetic number, because the mean of its divisors is an integer number (206655612171).

Almost surely, 2413311224341 is an apocalyptic number.

It is an amenable number.

413311224341 is a deficient number, since it is larger than the sum of its proper divisors (1).

413311224341 is an equidigital number, since it uses as much as digits as its factorization.

413311224341 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6912, while the sum is 29.

Adding to 413311224341 its reverse (143422113314), we get a palindrome (556733337655).

The spelling of 413311224341 in words is "four hundred thirteen billion, three hundred eleven million, two hundred twenty-four thousand, three hundred forty-one".