4134113120 has 24 divisors (see below), whose sum is σ = 9766842624. Its totient is φ = 1653645184.

The previous prime is 4134113117. The next prime is 4134113129. The reversal of 4134113120 is 213114314.

It is a super-2 number, since 2×4134113120² = 34181782577912268800, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 4134113092 and 4134113101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4134113129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12918944 + ... + 12919263.

It is an arithmetic number, because the mean of its divisors is an integer number (406951776).

Almost surely, 2^4134113120 is an apocalyptic number.

4134113120 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

4134113120 is an abundant number, since it is smaller than the sum of its proper divisors (5632729504).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

4134113120 is a wasteful number, since it uses less digits than its factorization.

4134113120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25838222 (or 25838214 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

The square root of 4134113120 is about 64297.0692955752. The cubic root of 4134113120 is about 1604.9473325044.

Adding to 4134113120 its reverse (213114314), we get a palindrome (4347227434).

The spelling of 4134113120 in words is "four billion, one hundred thirty-four million, one hundred thirteen thousand, one hundred twenty".