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413521550345117 is a prime number
BaseRepresentation
bin101111000000110000111110…
…1000111011000001110011101
32000020011021101211202022121002
41132001201331013120032131
5413200114113342020432
64023253102213320045
7153046642340331044
oct13601417507301635
92006137354668532
10413521550345117
1110a84056075a065
123a4672b6636025
1314997bb7c9a326
14741879aa2555b
1532c19a0305e62
hex178187d1d839d

413521550345117 has 2 divisors, whose sum is σ = 413521550345118. Its totient is φ = 413521550345116.

The previous prime is 413521550345011. The next prime is 413521550345119. The reversal of 413521550345117 is 711543055125314.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 366216578409796 + 47304971935321 = 19136786^2 + 6877861^2 .

It is a cyclic number.

It is not a de Polignac number, because 413521550345117 - 210 = 413521550344093 is a prime.

Together with 413521550345119, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (413521550345119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 206760775172558 + 206760775172559.

It is an arithmetic number, because the mean of its divisors is an integer number (206760775172559).

Almost surely, 2413521550345117 is an apocalyptic number.

It is an amenable number.

413521550345117 is a deficient number, since it is larger than the sum of its proper divisors (1).

413521550345117 is an equidigital number, since it uses as much as digits as its factorization.

413521550345117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1260000, while the sum is 47.

The spelling of 413521550345117 in words is "four hundred thirteen trillion, five hundred twenty-one billion, five hundred fifty million, three hundred forty-five thousand, one hundred seventeen".