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4154213981 is a prime number
BaseRepresentation
bin1111011110011100…
…0100011001011101
3101201111212221021002
43313213010121131
532001434321411
61524115120045
7204642144011
oct36747043135
911644787232
104154213981
111841a444a5
1297b2a3025
135128676a8
142b5a18541
15194a8833b
hexf79c465d

4154213981 has 2 divisors, whose sum is σ = 4154213982. Its totient is φ = 4154213980.

The previous prime is 4154213951. The next prime is 4154213983. The reversal of 4154213981 is 1893124514.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2564916025 + 1589297956 = 50645^2 + 39866^2 .

It is a cyclic number.

It is not a de Polignac number, because 4154213981 - 226 = 4087105117 is a prime.

It is a super-2 number, since 2×41542139812 = 34514987599871736722, which contains 22 as substring.

Together with 4154213983, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4154213983) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2077106990 + 2077106991.

It is an arithmetic number, because the mean of its divisors is an integer number (2077106991).

Almost surely, 24154213981 is an apocalyptic number.

It is an amenable number.

4154213981 is a deficient number, since it is larger than the sum of its proper divisors (1).

4154213981 is an equidigital number, since it uses as much as digits as its factorization.

4154213981 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 34560, while the sum is 38.

The square root of 4154213981 is about 64453.1921707529. The cubic root of 4154213981 is about 1607.5443165861.

The spelling of 4154213981 in words is "four billion, one hundred fifty-four million, two hundred thirteen thousand, nine hundred eighty-one".