Base | Representation |
---|---|
bin | 10010111001011010010100… |
… | …00100101001001011000000 |
3 | 12110010121211222022222000211 |
4 | 21130231022010221023000 |
5 | 20421314221114220000 |
6 | 224214043234523504 |
7 | 11516152624135351 |
oct | 1134551204511300 |
9 | 173117758288024 |
10 | 41555051320000 |
11 | 1227144214aa39 |
12 | 47b1792736594 |
13 | 1a2581710a81a |
14 | a393bd295d28 |
15 | 4c0e2014d7ba |
hex | 25cb4a1292c0 |
41555051320000 has 70 divisors (see below), whose sum is σ = 103043021981108. Its totient is φ = 16622020512000.
The previous prime is 41555051319979. The next prime is 41555051320001. The reversal of 41555051320000 is 2315055514.
It is not an unprimeable number, because it can be changed into a prime (41555051320001) by changing a digit.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 519398142 + ... + 519478141.
Almost surely, 241555051320000 is an apocalyptic number.
41555051320000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
41555051320000 is an abundant number, since it is smaller than the sum of its proper divisors (61487970661108).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
41555051320000 is an equidigital number, since it uses as much as digits as its factorization.
41555051320000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1038876315 (or 1038876290 counting only the distinct ones).
The product of its (nonzero) digits is 15000, while the sum is 31.
Adding to 41555051320000 its reverse (2315055514), we get a palindrome (41557366375514).
The spelling of 41555051320000 in words is "forty-one trillion, five hundred fifty-five billion, fifty-one million, three hundred twenty thousand".
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