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4199312981 is a prime number
BaseRepresentation
bin1111101001001100…
…0110111001010101
3101211122202012110102
43322103012321111
532100011003411
61532405503445
7206030366663
oct37223067125
911748665412
104199312981
111865447aa6
12992411b85
1351bcc80a6
142bb9d7c33
151989e5d3b
hexfa4c6e55

4199312981 has 2 divisors, whose sum is σ = 4199312982. Its totient is φ = 4199312980.

The previous prime is 4199312969. The next prime is 4199312993. The reversal of 4199312981 is 1892139914.

It is a balanced prime because it is at equal distance from previous prime (4199312969) and next prime (4199312993).

It can be written as a sum of positive squares in only one way, i.e., 4128062500 + 71250481 = 64250^2 + 8441^2 .

It is a cyclic number.

It is not a de Polignac number, because 4199312981 - 214 = 4199296597 is a prime.

It is a super-2 number, since 2×41993129812 = 35268459024790212722, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4199312941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2099656490 + 2099656491.

It is an arithmetic number, because the mean of its divisors is an integer number (2099656491).

Almost surely, 24199312981 is an apocalyptic number.

It is an amenable number.

4199312981 is a deficient number, since it is larger than the sum of its proper divisors (1).

4199312981 is an equidigital number, since it uses as much as digits as its factorization.

4199312981 is an evil number, because the sum of its binary digits is even.

The product of its digits is 139968, while the sum is 47.

The square root of 4199312981 is about 64802.1063006443. The cubic root of 4199312981 is about 1613.3406685182.

The spelling of 4199312981 in words is "four billion, one hundred ninety-nine million, three hundred twelve thousand, nine hundred eighty-one".