Base | Representation |
---|---|
bin | 10011001010000000011111… |
… | …10110001110101100111000 |
3 | 12112011010202221110011020111 |
4 | 21211000033312032230320 |
5 | 21010140111102112100 |
6 | 225332033100434104 |
7 | 11605311221326105 |
oct | 1145001766165470 |
9 | 175133687404214 |
10 | 42125305113400 |
11 | 12471272594213 |
12 | 48841bb548934 |
13 | 1a67526143142 |
14 | a58c38ab7aac |
15 | 4d0b987c56ba |
hex | 26500fd8eb38 |
42125305113400 has 48 divisors (see below), whose sum is σ = 98093654026200. Its totient is φ = 16823916516480.
The previous prime is 42125305113373. The next prime is 42125305113403. The reversal of 42125305113400 is 431150352124.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (42125305113403) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 163655635 + ... + 163912834.
Almost surely, 242125305113400 is an apocalyptic number.
42125305113400 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
42125305113400 is an abundant number, since it is smaller than the sum of its proper divisors (55968348912800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
42125305113400 is a wasteful number, since it uses less digits than its factorization.
42125305113400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 327569128 (or 327569119 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 42125305113400 its reverse (431150352124), we get a palindrome (42556455465524).
The spelling of 42125305113400 in words is "forty-two trillion, one hundred twenty-five billion, three hundred five million, one hundred thirteen thousand, four hundred".
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