Base | Representation |
---|---|
bin | 11001011001100… |
… | …011101110011111 |
3 | 1002200211122221000 |
4 | 121121203232133 |
5 | 1333042132320 |
6 | 110141241343 |
7 | 13363022331 |
oct | 3131435637 |
9 | 1080748830 |
10 | 426130335 |
11 | 1a95a3034 |
12 | ba863253 |
13 | 6a390137 |
14 | 40847451 |
15 | 27625c90 |
hex | 19663b9f |
426130335 has 32 divisors (see below), whose sum is σ = 771871680. Its totient is φ = 222977664.
The previous prime is 426130333. The next prime is 426130337. The reversal of 426130335 is 533031624.
It is a happy number.
426130335 is a `hidden beast` number, since 42 + 613 + 0 + 3 + 3 + 5 = 666.
It is an interprime number because it is at equal distance from previous prime (426130333) and next prime (426130337).
It is not a de Polignac number, because 426130335 - 21 = 426130333 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 426130299 and 426130308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (426130333) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 22624 + ... + 36933.
It is an arithmetic number, because the mean of its divisors is an integer number (24120990).
Almost surely, 2426130335 is an apocalyptic number.
426130335 is a gapful number since it is divisible by the number (45) formed by its first and last digit.
426130335 is a deficient number, since it is larger than the sum of its proper divisors (345741345).
426130335 is a wasteful number, since it uses less digits than its factorization.
426130335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59624 (or 59618 counting only the distinct ones).
The product of its (nonzero) digits is 6480, while the sum is 27.
The square root of 426130335 is about 20642.9245747786. The cubic root of 426130335 is about 752.5132487007.
Adding to 426130335 its reverse (533031624), we get a palindrome (959161959).
It can be divided in two parts, 4261 and 30335, that added together give a square (34596 = 1862).
The spelling of 426130335 in words is "four hundred twenty-six million, one hundred thirty thousand, three hundred thirty-five".
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