Base | Representation |
---|---|
bin | 10011011001001110011100… |
… | …10110000111010110001111 |
3 | 12121000010102211201121110001 |
4 | 21230213032112013112033 |
5 | 21042221444144420433 |
6 | 230412150425225131 |
7 | 11661141650161054 |
oct | 1154471626072617 |
9 | 177003384647401 |
10 | 42648192185743 |
11 | 12652aa671a931 |
12 | 49496093321a7 |
13 | 1aa4926b31271 |
14 | a7627d7d102b |
15 | 4de59d85d57d |
hex | 26c9ce58758f |
42648192185743 has 2 divisors, whose sum is σ = 42648192185744. Its totient is φ = 42648192185742.
The previous prime is 42648192185659. The next prime is 42648192185801. The reversal of 42648192185743 is 34758129184624.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 42648192185743 - 29 = 42648192185231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (42648192165743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21324096092871 + 21324096092872.
It is an arithmetic number, because the mean of its divisors is an integer number (21324096092872).
Almost surely, 242648192185743 is an apocalyptic number.
42648192185743 is a deficient number, since it is larger than the sum of its proper divisors (1).
42648192185743 is an equidigital number, since it uses as much as digits as its factorization.
42648192185743 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 92897280, while the sum is 64.
The spelling of 42648192185743 in words is "forty-two trillion, six hundred forty-eight billion, one hundred ninety-two million, one hundred eighty-five thousand, seven hundred forty-three".
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