Base | Representation |
---|---|
bin | 111110100100101101001… |
… | …110010010011000110111 |
3 | 120020002002212002210102102 |
4 | 332210231032102120313 |
5 | 1030422420332431401 |
6 | 13051222524532315 |
7 | 622444346201432 |
oct | 76445516223067 |
9 | 16202085083372 |
10 | 4300020983351 |
11 | 14086a081aa85 |
12 | 5954583b109b |
13 | 25264b093212 |
14 | 10c19d184819 |
15 | 76cc041156b |
hex | 3e92d392637 |
4300020983351 has 2 divisors, whose sum is σ = 4300020983352. Its totient is φ = 4300020983350.
The previous prime is 4300020983347. The next prime is 4300020983353. The reversal of 4300020983351 is 1533890200034.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4300020983351 - 22 = 4300020983347 is a prime.
Together with 4300020983353, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4300020983353) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2150010491675 + 2150010491676.
It is an arithmetic number, because the mean of its divisors is an integer number (2150010491676).
Almost surely, 24300020983351 is an apocalyptic number.
4300020983351 is a deficient number, since it is larger than the sum of its proper divisors (1).
4300020983351 is an equidigital number, since it uses as much as digits as its factorization.
4300020983351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 77760, while the sum is 38.
The spelling of 4300020983351 in words is "four trillion, three hundred billion, twenty million, nine hundred eighty-three thousand, three hundred fifty-one".
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