Base | Representation |
---|---|
bin | 110000111001000010000111… |
… | …0011110010010010001111000 |
3 | 2002101200110212020010001200221 |
4 | 1201302010032132102101320 |
5 | 422331423443414421100 |
6 | 4122350413534305424 |
7 | 156404106154360006 |
oct | 14162041636222170 |
9 | 2071613766101627 |
10 | 430051023201400 |
11 | 115033684210097 |
12 | 40296929658274 |
13 | 155c68396cb523 |
14 | 782a81b191a76 |
15 | 34ab93251301a |
hex | 187210e792478 |
430051023201400 has 96 divisors (see below), whose sum is σ = 1000306596124080. Its totient is φ = 171945073664000.
The previous prime is 430051023201377. The next prime is 430051023201413. The reversal of 430051023201400 is 4102320150034.
It is a super-2 number, since 2×4300510232014002 (a number of 30 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5954617290 + ... + 5954689510.
Almost surely, 2430051023201400 is an apocalyptic number.
430051023201400 is a gapful number since it is divisible by the number (40) formed by its first and last digit.
It is an amenable number.
430051023201400 is an abundant number, since it is smaller than the sum of its proper divisors (570255572922680).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
430051023201400 is a wasteful number, since it uses less digits than its factorization.
430051023201400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 84865 (or 84856 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 430051023201400 its reverse (4102320150034), we get a palindrome (434153343351434).
The spelling of 430051023201400 in words is "four hundred thirty trillion, fifty-one billion, twenty-three million, two hundred one thousand, four hundred".
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