Base | Representation |
---|---|
bin | 10011100100100001110010… |
… | …10101000101010110110101 |
3 | 12122101020211001121121011222 |
4 | 21302100321111011112311 |
5 | 21120102310214243242 |
6 | 231310413313040125 |
7 | 12031200302236442 |
oct | 1162207125052665 |
9 | 178336731547158 |
10 | 43036534134197 |
11 | 1279276761658a |
12 | 49b0928256045 |
13 | 1b02435102246 |
14 | a8ad9d5489c9 |
15 | 4e972ba2e5d2 |
hex | 2724395455b5 |
43036534134197 has 2 divisors, whose sum is σ = 43036534134198. Its totient is φ = 43036534134196.
The previous prime is 43036534134131. The next prime is 43036534134199. The reversal of 43036534134197 is 79143143563034.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 39413397004081 + 3623137130116 = 6278009^2 + 1903454^2 .
It is a cyclic number.
It is not a de Polignac number, because 43036534134197 - 28 = 43036534133941 is a prime.
Together with 43036534134199, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43036534134199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21518267067098 + 21518267067099.
It is an arithmetic number, because the mean of its divisors is an integer number (21518267067099).
Almost surely, 243036534134197 is an apocalyptic number.
It is an amenable number.
43036534134197 is a deficient number, since it is larger than the sum of its proper divisors (1).
43036534134197 is an equidigital number, since it uses as much as digits as its factorization.
43036534134197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9797760, while the sum is 53.
The spelling of 43036534134197 in words is "forty-three trillion, thirty-six billion, five hundred thirty-four million, one hundred thirty-four thousand, one hundred ninety-seven".
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