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43042122133 is a prime number
BaseRepresentation
bin101000000101100000…
…101010100110010101
311010002200100100112121
4220011200222212111
51201122240402013
631435010015541
73052424000353
oct500540524625
9133080310477
1043042122133
111728817946a
1284128775b1
13409c3c452a
14212461a7d3
1511bdaeb58d
hexa0582a995

43042122133 has 2 divisors, whose sum is σ = 43042122134. Its totient is φ = 43042122132.

The previous prime is 43042122127. The next prime is 43042122139. The reversal of 43042122133 is 33122124034.

It is a balanced prime because it is at equal distance from previous prime (43042122127) and next prime (43042122139).

It can be written as a sum of positive squares in only one way, i.e., 40607489169 + 2434632964 = 201513^2 + 49342^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43042122133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 43042122098 and 43042122107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43042122139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21521061066 + 21521061067.

It is an arithmetic number, because the mean of its divisors is an integer number (21521061067).

Almost surely, 243042122133 is an apocalyptic number.

It is an amenable number.

43042122133 is a deficient number, since it is larger than the sum of its proper divisors (1).

43042122133 is an equidigital number, since it uses as much as digits as its factorization.

43042122133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 43042122133 its reverse (33122124034), we get a palindrome (76164246167).

The spelling of 43042122133 in words is "forty-three billion, forty-two million, one hundred twenty-two thousand, one hundred thirty-three".