4311401910941 has 2 divisors, whose sum is σ = 4311401910942. Its totient is φ = 4311401910940.

The previous prime is 4311401910923. The next prime is 4311401910943. The reversal of 4311401910941 is 1490191041134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4213023079225 + 98378831716 = 2052565^2 + 313654^2 .

It is a cyclic number.

It is not a de Polignac number, because 4311401910941 - 2¹⁴ = 4311401894557 is a prime.

Together with 4311401910943, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 4311401910895 and 4311401910904.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4311401910943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2155700955470 + 2155700955471.

It is an arithmetic number, because the mean of its divisors is an integer number (2155700955471).

Almost surely, 2^{4311401910941} is an apocalyptic number.

It is an amenable number.

4311401910941 is a deficient number, since it is larger than the sum of its proper divisors (1).

4311401910941 is an equidigital number, since it uses as much as digits as its factorization.

4311401910941 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 38.

The spelling of 4311401910941 in words is "four trillion, three hundred eleven billion, four hundred one million, nine hundred ten thousand, nine hundred forty-one".