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43123214039 is a prime number
BaseRepresentation
bin101000001010010110…
…000000011011010111
311010022022221020201112
4220022112000123113
51201304020322124
631451024045235
73054430162043
oct501226003327
9133268836645
1043123214039
1117319a25a74
128435a6381b
1340b31478c9
1421312c9023
1511c5cb890e
hexa0a5806d7

43123214039 has 2 divisors, whose sum is σ = 43123214040. Its totient is φ = 43123214038.

The previous prime is 43123214003. The next prime is 43123214041. The reversal of 43123214039 is 93041232134.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43123214039 is a prime.

It is a super-2 number, since 2×431232140392 (a number of 22 digits) contains 22 as substring.

Together with 43123214041, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 43123213996 and 43123214014.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43123264039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21561607019 + 21561607020.

It is an arithmetic number, because the mean of its divisors is an integer number (21561607020).

Almost surely, 243123214039 is an apocalyptic number.

43123214039 is a deficient number, since it is larger than the sum of its proper divisors (1).

43123214039 is an equidigital number, since it uses as much as digits as its factorization.

43123214039 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 32.

The spelling of 43123214039 in words is "forty-three billion, one hundred twenty-three million, two hundred fourteen thousand, thirty-nine".