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43123452431 is a prime number
BaseRepresentation
bin101000001010010110…
…111010101000001111
311010022100101100201212
4220022112322220033
51201304100434211
631451033125035
73054432204053
oct501226725017
9133270340655
1043123452431
111731a079094
128435b5977b
1340b31cc277
14213134bc63
1511c5d1438b
hexa0a5baa0f

43123452431 has 2 divisors, whose sum is σ = 43123452432. Its totient is φ = 43123452430.

The previous prime is 43123452409. The next prime is 43123452433. The reversal of 43123452431 is 13425432134.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 43123452431 - 210 = 43123451407 is a prime.

It is a super-2 number, since 2×431234524312 (a number of 22 digits) contains 22 as substring.

Together with 43123452433, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43123452433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21561726215 + 21561726216.

It is an arithmetic number, because the mean of its divisors is an integer number (21561726216).

Almost surely, 243123452431 is an apocalyptic number.

43123452431 is a deficient number, since it is larger than the sum of its proper divisors (1).

43123452431 is an equidigital number, since it uses as much as digits as its factorization.

43123452431 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 34560, while the sum is 32.

Adding to 43123452431 its reverse (13425432134), we get a palindrome (56548884565).

The spelling of 43123452431 in words is "forty-three billion, one hundred twenty-three million, four hundred fifty-two thousand, four hundred thirty-one".