Base | Representation |
---|---|
bin | 1000000010111111… |
… | …11011010100111111 |
3 | 102011002001112021121 |
4 | 10001133323110333 |
5 | 32321422121413 |
6 | 1552403011411 |
7 | 212025235333 |
oct | 40137732477 |
9 | 12132045247 |
10 | 4320113983 |
11 | 1917656639 |
12 | a06969b67 |
13 | 53b042783 |
14 | 2cda817c3 |
15 | 1a4408b8d |
hex | 1017fb53f |
4320113983 has 2 divisors, whose sum is σ = 4320113984. Its totient is φ = 4320113982.
The previous prime is 4320113977. The next prime is 4320114017. The reversal of 4320113983 is 3893110234.
It is an a-pointer prime, because the next prime (4320114017) can be obtained adding 4320113983 to its sum of digits (34).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4320113983 - 29 = 4320113471 is a prime.
It is a super-2 number, since 2×43201139832 = 37326769652224248578, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4320113683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2160056991 + 2160056992.
It is an arithmetic number, because the mean of its divisors is an integer number (2160056992).
Almost surely, 24320113983 is an apocalyptic number.
4320113983 is a deficient number, since it is larger than the sum of its proper divisors (1).
4320113983 is an equidigital number, since it uses as much as digits as its factorization.
4320113983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 34.
The square root of 4320113983 is about 65727.5739929598. The cubic root of 4320113983 is about 1628.6648937876.
The spelling of 4320113983 in words is "four billion, three hundred twenty million, one hundred thirteen thousand, nine hundred eighty-three".
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