Base | Representation |
---|---|
bin | 101000010000110001… |
… | …100111000011011101 |
3 | 11010120211222002212112 |
4 | 220100301213003131 |
5 | 1202014131112222 |
6 | 31505440443405 |
7 | 3060210254411 |
oct | 502061470335 |
9 | 133524862775 |
10 | 43231113437 |
11 | 17374922426 |
12 | 8466019565 |
13 | 40cc5c5ac5 |
14 | 2141774d41 |
15 | 11d04cdbe2 |
hex | a10c670dd |
43231113437 has 2 divisors, whose sum is σ = 43231113438. Its totient is φ = 43231113436.
The previous prime is 43231113403. The next prime is 43231113439. The reversal of 43231113437 is 73431113234.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 41187078916 + 2044034521 = 202946^2 + 45211^2 .
It is a cyclic number.
It is not a de Polignac number, because 43231113437 - 210 = 43231112413 is a prime.
It is a super-3 number, since 3×432311134373 (a number of 33 digits) contains 333 as substring.
Together with 43231113439, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43231113439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21615556718 + 21615556719.
It is an arithmetic number, because the mean of its divisors is an integer number (21615556719).
Almost surely, 243231113437 is an apocalyptic number.
It is an amenable number.
43231113437 is a deficient number, since it is larger than the sum of its proper divisors (1).
43231113437 is an equidigital number, since it uses as much as digits as its factorization.
43231113437 is an evil number, because the sum of its binary digits is even.
The product of its digits is 18144, while the sum is 32.
The spelling of 43231113437 in words is "forty-three billion, two hundred thirty-one million, one hundred thirteen thousand, four hundred thirty-seven".
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