Base | Representation |
---|---|
bin | 10011101010011110110101… |
… | …01101110011101010111111 |
3 | 12200002210211222011222220221 |
4 | 21311033122231303222333 |
5 | 21131430240413210142 |
6 | 231544404533122211 |
7 | 12052031616551263 |
oct | 1165173255635277 |
9 | 180083758158827 |
10 | 43241105210047 |
11 | 128614a4663718 |
12 | 4a244ba789367 |
13 | 1b18807452314 |
14 | a96c487580a3 |
15 | 4eec01431767 |
hex | 2753dab73abf |
43241105210047 has 2 divisors, whose sum is σ = 43241105210048. Its totient is φ = 43241105210046.
The previous prime is 43241105210041. The next prime is 43241105210081. The reversal of 43241105210047 is 74001250114234.
It is an a-pointer prime, because the next prime (43241105210081) can be obtained adding 43241105210047 to its sum of digits (34).
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43241105210047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 43241105209994 and 43241105210021.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43241105210041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21620552605023 + 21620552605024.
It is an arithmetic number, because the mean of its divisors is an integer number (21620552605024).
Almost surely, 243241105210047 is an apocalyptic number.
43241105210047 is a deficient number, since it is larger than the sum of its proper divisors (1).
43241105210047 is an equidigital number, since it uses as much as digits as its factorization.
43241105210047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26880, while the sum is 34.
The spelling of 43241105210047 in words is "forty-three trillion, two hundred forty-one billion, one hundred five million, two hundred ten thousand, forty-seven".
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