43401241202040 has 48 divisors (see below), whose sum is σ = 141054033907800. Its totient is φ = 11573664320448.

The previous prime is 43401241202021. The next prime is 43401241202083. The reversal of 43401241202040 is 4020214210434.

43401241202040 is a `hidden beast` number, since 4 + 3 + 40 + 1 + 2 + 412 + 0 + 204 + 0 = 666.

It is a junction number, because it is equal to n+sod(n) for n = 43401241201995 and 43401241202013.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 60279501310 + ... + 60279502029.

Almost surely, 2^{43401241202040} is an apocalyptic number.

43401241202040 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

43401241202040 is an abundant number, since it is smaller than the sum of its proper divisors (97652792705760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

43401241202040 is a wasteful number, since it uses less digits than its factorization.

43401241202040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 120559003356 (or 120559003349 counting only the distinct ones).

The product of its (nonzero) digits is 6144, while the sum is 27.

Adding to 43401241202040 its reverse (4020214210434), we get a palindrome (47421455412474).

The spelling of 43401241202040 in words is "forty-three trillion, four hundred one billion, two hundred forty-one million, two hundred two thousand, forty".