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4342150200317 is a prime number
BaseRepresentation
bin111111001011111100010…
…100011111101111111101
3120101002211220122202111112
4333023330110133233331
51032120210422402232
613122431204131405
7625465346504036
oct77137424375775
916332756582445
104342150200317
11142454a652266
125a1655396b65
132566032c3077
14110238445a8d
1577e38cd24b2
hex3f2fc51fbfd

4342150200317 has 2 divisors, whose sum is σ = 4342150200318. Its totient is φ = 4342150200316.

The previous prime is 4342150200299. The next prime is 4342150200319. The reversal of 4342150200317 is 7130020512434.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3258508757956 + 1083641442361 = 1805134^2 + 1040981^2 .

It is a cyclic number.

It is not a de Polignac number, because 4342150200317 - 222 = 4342146006013 is a prime.

It is a super-2 number, since 2×43421502003172 (a number of 26 digits) contains 22 as substring.

Together with 4342150200319, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4342150200319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2171075100158 + 2171075100159.

It is an arithmetic number, because the mean of its divisors is an integer number (2171075100159).

Almost surely, 24342150200317 is an apocalyptic number.

It is an amenable number.

4342150200317 is a deficient number, since it is larger than the sum of its proper divisors (1).

4342150200317 is an equidigital number, since it uses as much as digits as its factorization.

4342150200317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20160, while the sum is 32.

The spelling of 4342150200317 in words is "four trillion, three hundred forty-two billion, one hundred fifty million, two hundred thousand, three hundred seventeen".