Base | Representation |
---|---|
bin | 1100101001001000101… |
… | …00101100110100011011 |
3 | 1112112021011022110212121 |
4 | 12110210110230310123 |
5 | 24104123140300011 |
6 | 531321111122111 |
7 | 43245602311222 |
oct | 6244424546433 |
9 | 1475234273777 |
10 | 434401103131 |
11 | 158257109346 |
12 | 70234073337 |
13 | 31c6b761578 |
14 | 1704cd31cb9 |
15 | b476ac7e71 |
hex | 652452cd1b |
434401103131 has 2 divisors, whose sum is σ = 434401103132. Its totient is φ = 434401103130.
The previous prime is 434401103057. The next prime is 434401103153. The reversal of 434401103131 is 131301104434.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 434401103131 - 211 = 434401101083 is a prime.
It is a super-2 number, since 2×4344011031312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 434401103096 and 434401103105.
It is not a weakly prime, because it can be changed into another prime (434401113131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217200551565 + 217200551566.
It is an arithmetic number, because the mean of its divisors is an integer number (217200551566).
Almost surely, 2434401103131 is an apocalyptic number.
434401103131 is a deficient number, since it is larger than the sum of its proper divisors (1).
434401103131 is an equidigital number, since it uses as much as digits as its factorization.
434401103131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 434401103131 its reverse (131301104434), we get a palindrome (565702207565).
The spelling of 434401103131 in words is "four hundred thirty-four billion, four hundred one million, one hundred three thousand, one hundred thirty-one".
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