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43513020581 is a prime number
BaseRepresentation
bin101000100001100101…
…000000000010100101
311011022111102110202212
4220201211000002211
51203103313124311
631553431013205
73100202400212
oct504145000245
9134274373685
1043513020581
11174a9a69438
12852450a205
134145b2a574
14216ad98b09
1511ea116c8b
hexa219400a5

43513020581 has 2 divisors, whose sum is σ = 43513020582. Its totient is φ = 43513020580.

The previous prime is 43513020553. The next prime is 43513020583. The reversal of 43513020581 is 18502031534.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25646421025 + 17866599556 = 160145^2 + 133666^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43513020581 is a prime.

It is a super-2 number, since 2×435130205812 (a number of 22 digits) contains 22 as substring.

Together with 43513020583, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43513020583) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21756510290 + 21756510291.

It is an arithmetic number, because the mean of its divisors is an integer number (21756510291).

Almost surely, 243513020581 is an apocalyptic number.

It is an amenable number.

43513020581 is a deficient number, since it is larger than the sum of its proper divisors (1).

43513020581 is an equidigital number, since it uses as much as digits as its factorization.

43513020581 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 32.

The spelling of 43513020581 in words is "forty-three billion, five hundred thirteen million, twenty thousand, five hundred eighty-one".