43534130117 has 2 divisors, whose sum is σ = 43534130118. Its totient is φ = 43534130116.

The previous prime is 43534130099. The next prime is 43534130119. The reversal of 43534130117 is 71103143534.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 37959118561 + 5575011556 = 194831^2 + 74666^2 .

It is a cyclic number.

It is not a de Polignac number, because 43534130117 - 2⁸ = 43534129861 is a prime.

Together with 43534130119, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43534130119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21767065058 + 21767065059.

It is an arithmetic number, because the mean of its divisors is an integer number (21767065059).

Almost surely, 2^43534130117 is an apocalyptic number.

It is an amenable number.

43534130117 is a deficient number, since it is larger than the sum of its proper divisors (1).

43534130117 is an equidigital number, since it uses as much as digits as its factorization.

43534130117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 32.

The spelling of 43534130117 in words is "forty-three billion, five hundred thirty-four million, one hundred thirty thousand, one hundred seventeen".