Base | Representation |
---|---|
bin | 101000111110101010… |
… | …111011010011111101 |
3 | 11012120111212011011111 |
4 | 220332222323103331 |
5 | 1210103241111331 |
6 | 32114104322021 |
7 | 3115250202163 |
oct | 507652732375 |
9 | 135514764144 |
10 | 44001113341 |
11 | 1772a532789 |
12 | 863ba73311 |
13 | 41c2ca3953 |
14 | 21b5b31233 |
15 | 1227dcbdb1 |
hex | a3eabb4fd |
44001113341 has 2 divisors, whose sum is σ = 44001113342. Its totient is φ = 44001113340.
The previous prime is 44001113339. The next prime is 44001113369. The reversal of 44001113341 is 14331110044.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 22095633316 + 21905480025 = 148646^2 + 148005^2 .
It is a cyclic number.
It is not a de Polignac number, because 44001113341 - 21 = 44001113339 is a prime.
Together with 44001113339, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (44001119341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22000556670 + 22000556671.
It is an arithmetic number, because the mean of its divisors is an integer number (22000556671).
Almost surely, 244001113341 is an apocalyptic number.
It is an amenable number.
44001113341 is a deficient number, since it is larger than the sum of its proper divisors (1).
44001113341 is an equidigital number, since it uses as much as digits as its factorization.
44001113341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 44001113341 its reverse (14331110044), we get a palindrome (58332223385).
The spelling of 44001113341 in words is "forty-four billion, one million, one hundred thirteen thousand, three hundred forty-one".
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