Base | Representation |
---|---|
bin | 110010000001100100010101… |
… | …0100111001110100000011111 |
3 | 2010200222111211022222120210122 |
4 | 1210003020222213032200133 |
5 | 430133242143241320221 |
6 | 4155502241104425155 |
7 | 161453255426415443 |
oct | 14403105247164037 |
9 | 2120874738876718 |
10 | 440020114401311 |
11 | 118227534308124 |
12 | 41426a1a0181bb |
13 | 15b6a946106912 |
14 | 7a931312a8823 |
15 | 35d0dedb62eab |
hex | 190322a9ce81f |
440020114401311 has 2 divisors, whose sum is σ = 440020114401312. Its totient is φ = 440020114401310.
The previous prime is 440020114401299. The next prime is 440020114401337. The reversal of 440020114401311 is 113104411020044.
It is a happy number.
It is an a-pointer prime, because the next prime (440020114401337) can be obtained adding 440020114401311 to its sum of digits (26).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 440020114401311 - 210 = 440020114400287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (440020114401341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 220010057200655 + 220010057200656.
It is an arithmetic number, because the mean of its divisors is an integer number (220010057200656).
Almost surely, 2440020114401311 is an apocalyptic number.
440020114401311 is a deficient number, since it is larger than the sum of its proper divisors (1).
440020114401311 is an equidigital number, since it uses as much as digits as its factorization.
440020114401311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 26.
Adding to 440020114401311 its reverse (113104411020044), we get a palindrome (553124525421355).
The spelling of 440020114401311 in words is "four hundred forty trillion, twenty billion, one hundred fourteen million, four hundred one thousand, three hundred eleven".
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