Search a number
-
+
443031210014189 is a prime number
BaseRepresentation
bin110010010111011110011110…
…1111001011011010111101101
32011002122100222202121101200212
41210232330331321123113231
5431032110404230423224
64210125421141432205
7162213643250006246
oct14456747571332755
92132570882541625
10443031210014189
11119188532286aa5
12418324bba0b665
13160288825c9b14
147b58b79a3dccd
1536343d2530d0e
hex192ef3de5b5ed

443031210014189 has 2 divisors, whose sum is σ = 443031210014190. Its totient is φ = 443031210014188.

The previous prime is 443031210014101. The next prime is 443031210014191. The reversal of 443031210014189 is 981410012130344.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 442912017975625 + 119192038564 = 21045475^2 + 345242^2 .

It is a cyclic number.

It is not a de Polignac number, because 443031210014189 - 228 = 443030941578733 is a prime.

Together with 443031210014191, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (443031210014089) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221515605007094 + 221515605007095.

It is an arithmetic number, because the mean of its divisors is an integer number (221515605007095).

Almost surely, 2443031210014189 is an apocalyptic number.

It is an amenable number.

443031210014189 is a deficient number, since it is larger than the sum of its proper divisors (1).

443031210014189 is an equidigital number, since it uses as much as digits as its factorization.

443031210014189 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 82944, while the sum is 41.

The spelling of 443031210014189 in words is "four hundred forty-three trillion, thirty-one billion, two hundred ten million, fourteen thousand, one hundred eighty-nine".