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443194921493 is a prime number
BaseRepresentation
bin1100111001100000111…
…10011101001000010101
31120100222000102201211222
412130300132131020111
524230130344441433
6535333445140125
744006532450512
oct6346036351025
91510860381758
10443194921493
11160a59a85225
1271a890ba645
1332a405a199c
1417644bd6309
15b7ddb28b98
hex673079d215

443194921493 has 2 divisors, whose sum is σ = 443194921494. Its totient is φ = 443194921492.

The previous prime is 443194921489. The next prime is 443194921511. The reversal of 443194921493 is 394129491344.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 286890926884 + 156303994609 = 535622^2 + 395353^2 .

It is a cyclic number.

It is not a de Polignac number, because 443194921493 - 22 = 443194921489 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (443194921193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221597460746 + 221597460747.

It is an arithmetic number, because the mean of its divisors is an integer number (221597460747).

Almost surely, 2443194921493 is an apocalyptic number.

It is an amenable number.

443194921493 is a deficient number, since it is larger than the sum of its proper divisors (1).

443194921493 is an equidigital number, since it uses as much as digits as its factorization.

443194921493 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3359232, while the sum is 53.

The spelling of 443194921493 in words is "four hundred forty-three billion, one hundred ninety-four million, nine hundred twenty-one thousand, four hundred ninety-three".