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4471130053471 is a prime number
BaseRepresentation
bin100000100010000010000…
…0111100101101101011111
3120211102202202000011201211
41001010010013211231133
51041223333243202341
613302001522045251
7641012525250244
oct101040407455537
916742682004654
104471130053471
111474217397a24
126026504a9827
13265819a254c3
1411659223b5cb
157b4872d5181
hex411041e5b5f

4471130053471 has 2 divisors, whose sum is σ = 4471130053472. Its totient is φ = 4471130053470.

The previous prime is 4471130053469. The next prime is 4471130053493. The reversal of 4471130053471 is 1743500311744.

It is a happy number.

4471130053471 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4471130053471 - 21 = 4471130053469 is a prime.

It is a super-3 number, since 3×44711300534713 (a number of 39 digits) contains 333 as substring.

Together with 4471130053469, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4471130053421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2235565026735 + 2235565026736.

It is an arithmetic number, because the mean of its divisors is an integer number (2235565026736).

Almost surely, 24471130053471 is an apocalyptic number.

4471130053471 is a deficient number, since it is larger than the sum of its proper divisors (1).

4471130053471 is an equidigital number, since it uses as much as digits as its factorization.

4471130053471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 141120, while the sum is 40.

The spelling of 4471130053471 in words is "four trillion, four hundred seventy-one billion, one hundred thirty million, fifty-three thousand, four hundred seventy-one".