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45533070493 is a prime number
BaseRepresentation
bin101010011001111110…
…111000010010011101
311100112021111122022021
4222121332320102131
51221222431223433
632530111420141
73201231466441
oct523176702235
9140467448267
1045533070493
111834625a879
1289a8b24651
1343a84a4981
1422bd392821
1512b763a22d
hexa99fb849d

45533070493 has 2 divisors, whose sum is σ = 45533070494. Its totient is φ = 45533070492.

The previous prime is 45533070439. The next prime is 45533070547. The reversal of 45533070493 is 39407033554.

It is a happy number.

Together with previous prime (45533070439) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (45533070439) and next prime (45533070547).

It can be written as a sum of positive squares in only one way, i.e., 26811442564 + 18721627929 = 163742^2 + 136827^2 .

It is a cyclic number.

It is not a de Polignac number, because 45533070493 - 217 = 45532939421 is a prime.

It is a super-3 number, since 3×455330704933 (a number of 33 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (45533070293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22766535246 + 22766535247.

It is an arithmetic number, because the mean of its divisors is an integer number (22766535247).

Almost surely, 245533070493 is an apocalyptic number.

It is an amenable number.

45533070493 is a deficient number, since it is larger than the sum of its proper divisors (1).

45533070493 is an equidigital number, since it uses as much as digits as its factorization.

45533070493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 680400, while the sum is 43.

The spelling of 45533070493 in words is "forty-five billion, five hundred thirty-three million, seventy thousand, four hundred ninety-three".