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46781532047231 is a prime number
BaseRepresentation
bin10101010001100001011001…
…00110011000011101111111
320010122021022101220002122122
422220300230212120131333
522112432034201002411
6243255050015233155
712565565655254102
oct1250605446303577
9203567271802578
1046781532047231
11139a6a33280a33
1252b66a85187bb
13201463072c307
14b7a3499d0739
15561d659a59db
hex2a8c2c99877f

46781532047231 has 2 divisors, whose sum is σ = 46781532047232. Its totient is φ = 46781532047230.

The previous prime is 46781532047213. The next prime is 46781532047249. The reversal of 46781532047231 is 13274023518764.

Together with previous prime (46781532047213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (46781532047213) and next prime (46781532047249).

It is a cyclic number.

It is not a de Polignac number, because 46781532047231 - 26 = 46781532047167 is a prime.

It is a super-2 number, since 2×467815320472312 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (46781532047251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23390766023615 + 23390766023616.

It is an arithmetic number, because the mean of its divisors is an integer number (23390766023616).

Almost surely, 246781532047231 is an apocalyptic number.

46781532047231 is a deficient number, since it is larger than the sum of its proper divisors (1).

46781532047231 is an equidigital number, since it uses as much as digits as its factorization.

46781532047231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6773760, while the sum is 53.

The spelling of 46781532047231 in words is "forty-six trillion, seven hundred eighty-one billion, five hundred thirty-two million, forty-seven thousand, two hundred thirty-one".