Base | Representation |
---|---|
bin | 101100000000000011… |
… | …010101000110111111 |
3 | 11111221121202202000102 |
4 | 230000003111012333 |
5 | 1233224322410101 |
6 | 33412043151315 |
7 | 3261534143564 |
oct | 540003250677 |
9 | 144847682012 |
10 | 47245513151 |
11 | 19044951341 |
12 | 91a651553b |
13 | 45bc1b9855 |
14 | 240299686b |
15 | 1367b4a86b |
hex | b000d51bf |
47245513151 has 2 divisors, whose sum is σ = 47245513152. Its totient is φ = 47245513150.
The previous prime is 47245513129. The next prime is 47245513153. The reversal of 47245513151 is 15131554274.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-47245513151 is a prime.
Together with 47245513153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (47245513153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23622756575 + 23622756576.
It is an arithmetic number, because the mean of its divisors is an integer number (23622756576).
Almost surely, 247245513151 is an apocalyptic number.
47245513151 is a deficient number, since it is larger than the sum of its proper divisors (1).
47245513151 is an equidigital number, since it uses as much as digits as its factorization.
47245513151 is an evil number, because the sum of its binary digits is even.
The product of its digits is 84000, while the sum is 38.
The spelling of 47245513151 in words is "forty-seven billion, two hundred forty-five million, five hundred thirteen thousand, one hundred fifty-one".
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