Search a number
-
+
47504023114781 is a prime number
BaseRepresentation
bin10101100110100011001000…
…11011000101010000011101
320020012100012001022002220102
422303101210123011100131
522211301214404133111
6245011014050230445
713002023656101122
oct1263214433052035
9206170161262812
1047504023114781
1114155385691562
1253b2721285425
1320677c169663c
14ba32c7d84749
15575a4e33d13b
hex2b34646c541d

47504023114781 has 2 divisors, whose sum is σ = 47504023114782. Its totient is φ = 47504023114780.

The previous prime is 47504023114729. The next prime is 47504023114783. The reversal of 47504023114781 is 18741132040574.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 45986775636025 + 1517247478756 = 6781355^2 + 1231766^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-47504023114781 is a prime.

It is a super-2 number, since 2×475040231147812 (a number of 28 digits) contains 22 as substring.

Together with 47504023114783, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (47504023114783) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 23752011557390 + 23752011557391.

It is an arithmetic number, because the mean of its divisors is an integer number (23752011557391).

Almost surely, 247504023114781 is an apocalyptic number.

It is an amenable number.

47504023114781 is a deficient number, since it is larger than the sum of its proper divisors (1).

47504023114781 is an equidigital number, since it uses as much as digits as its factorization.

47504023114781 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 752640, while the sum is 47.

The spelling of 47504023114781 in words is "forty-seven trillion, five hundred four billion, twenty-three million, one hundred fourteen thousand, seven hundred eighty-one".