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4812825270941 is a prime number
BaseRepresentation
bin100011000001001001010…
…1111011001101010011101
3122001002202001211201011122
41012002102233121222131
51112323131232132231
614122551552300325
71004500203546452
oct106022257315235
918032661751148
104812825270941
111596120439236
126589115416a5
1328bb02b9a10c
14128d28b49829
15852d51d777b
hex46092bd9a9d

4812825270941 has 2 divisors, whose sum is σ = 4812825270942. Its totient is φ = 4812825270940.

The previous prime is 4812825270829. The next prime is 4812825270947. The reversal of 4812825270941 is 1490725282184.

It is a happy number.

4812825270941 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4423361906041 + 389463364900 = 2103179^2 + 624070^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4812825270941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4812825270947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2406412635470 + 2406412635471.

It is an arithmetic number, because the mean of its divisors is an integer number (2406412635471).

Almost surely, 24812825270941 is an apocalyptic number.

It is an amenable number.

4812825270941 is a deficient number, since it is larger than the sum of its proper divisors (1).

4812825270941 is an equidigital number, since it uses as much as digits as its factorization.

4812825270941 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2580480, while the sum is 53.

The spelling of 4812825270941 in words is "four trillion, eight hundred twelve billion, eight hundred twenty-five million, two hundred seventy thousand, nine hundred forty-one".