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481700364262541 is a prime number
BaseRepresentation
bin110110110000110101001101…
…1000110011001110010001101
32100011120002211121110102020222
41231201222123012121302031
51001114134321222400131
64424254031542521125
7203314463035604324
oct15541523306316215
92304502747412228
10481700364262541
1112a536a827a6146
12460389114361a5
13178a21c34236a8
1486d45ca08b0bb
153aa51ea33a87b
hex1b61a9b199c8d

481700364262541 has 2 divisors, whose sum is σ = 481700364262542. Its totient is φ = 481700364262540.

The previous prime is 481700364262529. The next prime is 481700364262543. The reversal of 481700364262541 is 145262463007184.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 290537138522500 + 191163225740041 = 17045150^2 + 13826179^2 .

It is a cyclic number.

It is not a de Polignac number, because 481700364262541 - 26 = 481700364262477 is a prime.

Together with 481700364262543, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (481700364262543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 240850182131270 + 240850182131271.

It is an arithmetic number, because the mean of its divisors is an integer number (240850182131271).

Almost surely, 2481700364262541 is an apocalyptic number.

It is an amenable number.

481700364262541 is a deficient number, since it is larger than the sum of its proper divisors (1).

481700364262541 is an equidigital number, since it uses as much as digits as its factorization.

481700364262541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7741440, while the sum is 53.

The spelling of 481700364262541 in words is "four hundred eighty-one trillion, seven hundred billion, three hundred sixty-four million, two hundred sixty-two thousand, five hundred forty-one".